(2x^2-6x-56)(3x-21)

asked by guest
on Apr 06, 2025 at 7:57 am



You asked:

Evaluate the expression: (2x2−6x−56)(3x−21)\left(2 {x}^{2} - 6 x - 56\right) \left(3 x - 21\right)

MathBot Answer:

Evaluated



(2x2−6x−56)(3x−21)=(3x−21)(2x2−6x−56)\displaystyle \left(2 {x}^{2} - 6 x - 56\right) \left(3 x - 21\right) = \left(3 x - 21\right) \left(2 x^{2} - 6 x - 56\right)

Expanded

(2x2−6x−56)(3x−21)=6x3−60x2−42x+1176\left(2 {x}^{2} - 6 x - 56\right) \left(3 x - 21\right) = 6 x^{3} - 60 x^{2} - 42 x + 1176

Factored

(2x2−6x−56)(3x−21)=6(x−7)2(x+4)\left(2 {x}^{2} - 6 x - 56\right) \left(3 x - 21\right) = 6 \left(x - 7\right)^{2} \left(x + 4\right)

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