Find the value of 2x²-3xy when x=√2+3 and y=√2-2
You asked:
Calculate the value of \(2 {x}^{2} - 3 x y\) when \(x = \sqrt{2} + 3\) and \(y = \sqrt{2} - 2\).
MathBot Answer:
\[2 {x}^{2} - 3 x y = 2 {\left( \sqrt{2} + 3 \right)}^{2} - 3 \cdot \left(\sqrt{2} + 3\right) \cdot \left(\sqrt{2} - 2\right) = - 3 \left(-2 + \sqrt{2}\right) \left(\sqrt{2} + 3\right) + 2 \left(\sqrt{2} + 3\right)^{2}\]