ln(1+1/x)

asked by guest
on Apr 05, 2025 at 12:15 am



You asked:

Evaluate the expression: ln⁡(1+1x)\ln\left( 1 + \frac{1}{x} \right)

MathBot Answer:

ln⁡(1+1x)=log⁡(1+1x)\ln\left( 1 + \frac{1}{x} \right) = \log{\left(1 + \frac{1}{x} \right)}

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