Find the equation of the line that passes through the point (-3, -10) and has slope 4.
You asked:
Find an equation of the line through the point \((-3, -10)\) with slope \(4\).
MathBot Answer:
Standard Form:
$$\begin{aligned}Ax + By + C = 0\end{aligned}$$$$\begin{aligned} \text{Slope} &= -\frac{A}{B} \\ -\frac{A}{B} &= \frac{4}{1} \\ A =& -4, B = 1 \end{aligned}$$$$\begin{aligned}-4 x + 1 y + C &= 0 \\ -4(-3) + 1(-10) + C &= 0 \\ 12 + -10 + C &= 0 \\ 12 + C &= 10 \\ C &= -2 \end{aligned}$$An equation of the line in standard form is: $- 4 x + y - 2 = 0$.
Slope-Intercept Form:
$$\begin{aligned} y = mx+b\end{aligned}$$$$\begin{aligned}y &= 4x + b \\ -10 &= 4 \times -3 + b \\ -10 &= -12 + b \\ b &= 2 \end{aligned}$$The slope-intercept form of the line is: $y = 4 x + 2$.