2ˣ (3²ˣ) = 5 (7ˣ)

asked by guest
on Mar 31, 2025 at 12:21 am



You asked:

Solve the equation 2x⋅32x=5⋅7x{2}^{x} \cdot {3}^{2 x} = 5 \cdot {7}^{x} for the variable xx.

MathBot Answer:

The solution is: x=log⁡(5)−log⁡(7)+log⁡(18)≈1.7040798x = \frac{\log{\left(5 \right)}}{- \log{\left(7 \right)} + \log{\left(18 \right)}} \approx 1.7040798

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