-5(2h+3i)
You asked:
Evaluate the expression: \(-\left( 5 \cdot \left(2 h + 3 i\right) \right)\)
MathBot Answer:
Evaluated
\(\displaystyle -\left( 5 \cdot \left(2 h + 3 i\right) \right) = - 10 h - 15 i \)
Expanded
\[-\left( 5 \cdot \left(2 h + 3 i\right) \right) = - 10 h - 15 i\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).