4cos2x=2sin2x
You asked:
Solve the equation \(4 \cdot \cos\left( 2 x \right) = 2 \cdot \sin\left( 2 x \right)\) for the variable \(x\).
MathBot Answer:
The real solutions are: \[\begin{aligned}x &= \left\{\frac{\arctan{\left(2 \right)}}{2} + \pi n\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{3.1415927 n + 0.55357436\; \middle|\; n \in \mathbb{Z}\right\}\\x &= \left\{\frac{\pi}{2} + \frac{\arctan{\left(2 \right)}}{2} + \pi n\; \middle|\; n \in \mathbb{Z}\right\} \approx \left\{3.1415927 n + 2.1243707\; \middle|\; n \in \mathbb{Z}\right\}\end{aligned}\]