\int \left(x^2-2x+3\right)2^xdx

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on Mar 30, 2025 at 4:46 am



You asked:

Evaluate the integral: ∫(x2−2x+3)⋅2xdx\int{\left({x}^{2} - 2 x + 3\right) \cdot {2}^{x}}dx

MathBot Answer:

Antiderivative

∫(x2−2x+3)⋅2xdx=2x(2+2log⁡(2)+3log⁡(2)2+x2log⁡(2)2−2log⁡(2)2x−2xlog⁡(2))log⁡(2)3+C\int{\left({x}^{2} - 2 x + 3\right) \cdot {2}^{x}}dx = \frac{2^{x} \left(2 + 2 \log{\left(2 \right)} + 3 \log{\left(2 \right)}^{2} + x^{2} \log{\left(2 \right)}^{2} - 2 \log{\left(2 \right)}^{2} x - 2 x \log{\left(2 \right)}\right)}{\log{\left(2 \right)}^{3}} + C

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