Math Problem Solver

$$360 - 291=69$$

$$\begin{aligned} \overset{\mathtt{{\scriptscriptstyle 2}}}{\cancel{\mathtt{3}}}\overset{\mathtt{{\scriptscriptstyle 15}}}{\cancel{\mathtt{6}}}\overset{\mathtt{{\scriptscriptstyle 10}}}{\cancel{\mathtt{0}}}\\ \mathtt{-\phantom{0}}\mathtt{2}\mathtt{9}\mathtt{1}\\ \hline \mathtt{0}\mathtt{6}\mathtt{9} \end{aligned}$$

Borrow $10^{1}$, resulting in $5$ in the $10^{1}$ place, and $10$ in the $10^{0}$ place.

$9$ is the digit in the $10^{0}$ place. $10 \times 10^{0} - 1 \times 10^{0} = 9 \times 10^{0}$.

Borrow $10^{2}$, resulting in $2$ in the $10^{2}$ place, and $15$ in the $10^{1}$ place.

$6$ is the digit in the $10^{1}$ place. $15 \times 10^{1} - 9 \times 10^{1} = 6 \times 10^{1}$.

$0$ is the digit in the $10^{2}$ place. $2 \times 10^{2} - 2 \times 10^{2} = 0 \times 10^{2}$.