(2r+s)(4r-3s)

asked by guest
on Mar 17, 2025 at 6:49 am



You asked:

Evaluate the expression: (2r+s)(4r−3s)\left(2 r + s\right) \left(4 r - 3 s\right)

MathBot Answer:

Evaluated



(2r+s)(4r−3s)=(2r+s)(4r−3s)\displaystyle \left(2 r + s\right) \left(4 r - 3 s\right) = \left(2 r + s\right) \left(4 r - 3 s\right)

Expanded

(2r+s)(4r−3s)=8r2−2rs−3s2\left(2 r + s\right) \left(4 r - 3 s\right) = 8 r^{2} - 2 r s - 3 s^{2}

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