4/9p^2+p-1

asked by guest
on Sep 21, 2024 at 4:53 am



You asked:

Evaluate the expression: \(\frac{4}{9 \cdot {p}^{2}} + p - 1\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{4}{9 \cdot {p}^{2}} + p - 1 = p - 1 + \frac{4}{9 p^{2}} \)

Factored

\[\frac{4}{9 \cdot {p}^{2}} + p - 1 = \frac{9 p^{3} - 9 p^{2} + 4}{9 p^{2}}\]

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