5x-8y=1

4x-2y=26

solve by elimination method

asked by guest
on Mar 23, 2025 at 12:51 pm



You asked:

Solve the system of equations 5x8y=15 x - 8 y = 1, 4x2y=264 x - 2 y = 26 by elimination.

MathBot Answer:

x=10311y=6311\begin{aligned}x &= \frac{103}{11}\\y &= \frac{63}{11}\end{aligned}

5x8y=14x2y=26\begin{aligned}5 x - 8 y &= 1\\4 x - 2 y &= 26\end{aligned}

Eliminate xx from equation 2 by multiply both sides of equation 1 by 45- \frac{4}{5}, and adding the results to both sides of equation 2.

5x8y=122y5=1265\begin{aligned}5 x - 8 y &= 1\\\frac{22 y}{5} &= \frac{126}{5}\end{aligned}

Solve equation 2 for yy, and substitute the solution into the remaining equations.

5x=51511y=6311\begin{aligned}5 x &= \frac{515}{11}\\y &= \frac{63}{11}\end{aligned}

Solve equation 1 for the remaining unknown xx.

x=10311y=6311\begin{aligned}x &= \frac{103}{11}\\y &= \frac{63}{11}\end{aligned}