Math Problem Solver

Slope-Intercept Form:

$$\begin{aligned} y = mx+b\end{aligned}$$$$\begin{aligned}y &= 1x + b \\ -1 &= 1 \times -4 + b \\ -1 &= -4 + b \\ b &= 3 \end{aligned}$$An equation of the line in slope-intercept form is: $y = x + 3$

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Point-Slope Form:

$$\begin{aligned} y - y_{1} = m(x - x_{1}) \end{aligned}$$$$ \text{where m } = 1, \text{ } x_{1} = -4, \text{ and } y_{1} = -1 $$An equation of the line in point-slope form is: $y + 1 = x + 4$

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Standard Form:

$$\begin{aligned}Ax + By + C = 0\end{aligned}$$$$\begin{aligned} \text{Slope} &= -\frac{A}{B} \\ -\frac{A}{B} &= \frac{1}{1} \\ A = -1, B = 1 \end{aligned}$$$$\begin{aligned}-1 x + 1 y + C &= 0 \\ -1(-4) + 1(-1) + C &= 0 \\ 4 + -1 + C &= 0 \\ 4 + C &= 1 \\ C &= -3 \end{aligned}$$An equation of the line in standard form is: $x - y + 3 = 0$