factorize (3ab-2ac)(b+c)
asked by guest on Mar 28, 2025 at 6:41 am
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MathBot Answer:
The polynomial factors into the product: (3ab−2ac)(b+c)=a(3b−2c)(b+c)\left(3 a b - 2 a c\right) \left(b + c\right) = a \left(3 b - 2 c\right) \left(b + c\right)(3ab−2ac)(b+c)=a(3b−2c)(b+c)