Solve the following: $\frac{sin (2x)}{sin x}$ - $\frac{cos (2x)}{cos x}$

asked by scollins
on Oct 06, 2024 at 3:35 pm



You asked:

Evaluate the expression: \(\frac{\sin\left( 2 x \right)}{\sin\left( x \right)} - \frac{\cos\left( 2 x \right)}{\cos\left( x \right)}\)

MathBot Answer:

Simplified: \[\frac{\sin\left( 2 x \right)}{\sin\left( x \right)} - \frac{\cos\left( 2 x \right)}{\cos\left( x \right)} = \frac{1}{\cos{\left(x \right)}}\]

Factored: \[\frac{\sin\left( 2 x \right)}{\sin\left( x \right)} - \frac{\cos\left( 2 x \right)}{\cos\left( x \right)} = - \frac{- \sin{\left(2 x \right)} \cos{\left(x \right)} + \sin{\left(x \right)} \cos{\left(2 x \right)}}{\sin{\left(x \right)} \cos{\left(x \right)}}\]

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