\frac{\left(9x^2-y^2\right)}{y^2-2xy-3x^2}
You asked:
Evaluate the expression: \(\frac{9 {x}^{2} - {y}^{2}}{{y}^{2} - 2 x y - 3 {x}^{2}}\)
MathBot Answer:
Evaluated
\(\displaystyle \frac{9 {x}^{2} - {y}^{2}}{{y}^{2} - 2 x y - 3 {x}^{2}} = \frac{9 x^{2} - y^{2}}{- 3 x^{2} - 2 x y + y^{2}} \)
Expanded
\[\frac{9 {x}^{2} - {y}^{2}}{{y}^{2} - 2 x y - 3 {x}^{2}} = \frac{9 x^{2}}{- 3 x^{2} - 2 x y + y^{2}} - \frac{y^{2}}{- 3 x^{2} - 2 x y + y^{2}}\]
Factored
\[\frac{9 {x}^{2} - {y}^{2}}{{y}^{2} - 2 x y - 3 {x}^{2}} = - \frac{3 x + y}{x + y}\]