9*6^n/35 - 2/5 + (-1)^n/7
expanded
asked by guest on Mar 28, 2025 at 6:20 pm
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MathBot Answer:
(−1)n7+9⋅6n35−25=(−1)n7+9⋅6n35−25\frac{\left(-1\right)^{n}}{7} + \frac{9 \cdot 6^{n}}{35} - \frac{2}{5} = \frac{\left(-1\right)^{n}}{7} + \frac{9 \cdot 6^{n}}{35} - \frac{2}{5}7(−1)n+359⋅6n−52=7(−1)n+359⋅6n−52