x ^ { 2 } -2x-8 \div x+2
asked by guest on Mar 26, 2025 at 8:41 pm
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MathBot Answer:
x2−2x−8x+2=x2−2x+2−8x\displaystyle {x}^{2} - 2 x - \frac{8}{x} + 2 = x^{2} - 2 x + 2 - \frac{8}{x} x2−2x−x8+2=x2−2x+2−x8
x2−2x−8x+2=x3−2x2+2x−8x{x}^{2} - 2 x - \frac{8}{x} + 2 = \frac{x^{3} - 2 x^{2} + 2 x - 8}{x}x2−2x−x8+2=xx3−2x2+2x−8
