(x+1)(x−2)2x3−x2−5x+15
asked by guest
on Jan 28, 2025 at 2:13 pm
You asked:
Evaluate the expression:
(x+1)(x−2)2x3−x2−5x+15
MathBot Answer:
Evaluated
(x+1)(x−2)2x3−x2−5x+15=(x−2)2(x+1)x3−x2−5x+15
Expanded
(x+1)(x−2)2x3−x2−5x+15=x3−3x2+4x3−x3−3x2+4x2−x3−3x2+45x+x3−3x2+415