(2 t\sqrt{t} -3) 2^{2} - t 2^{2} = 0

asked by menachem48z
on Apr 04, 2025 at 11:14 pm



You asked:

Solve the equation (2t−3)2−t2=0{\left( 2 \sqrt{t} - 3 \right)}^{2} - {t}^{2} = 0 for the variable tt.

MathBot Answer:

The 3 solutions to the equation are: t=1t=−1−22i=−1−2.8284271it=−1+22i=−1+2.8284271i\begin{aligned}t &= 1\\t &= -1 - 2 \sqrt{2} i = -1 -2.8284271 i\\t &= -1 + 2 \sqrt{2} i = -1 + 2.8284271 i\end{aligned}

ii is the imaginary unit, defined as i2=−1i^2 = -1.

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