1649676

36814420

30324376

5608252

6749810

2395199

1463466213318297

.482427779239445

29742÷5205053

759139÷760845

asked by guest
on Nov 28, 2024 at 3:34 am



MathBot Answer:

Original numbers in ascending order: \(\frac{29742}{5205053}\), \(.482427779239445\), \(\frac{759139}{760845}\), \(1649676\), \(2395199\), \(5608252\), \(6749810\), \(30324376\), \(36814420\), \(1463466213318297\)
Sum: \( \frac{231827025805447815633938549528711882730773}{158409541991400000000000000} \approx 1.46346629686003 \cdot 10^{15} \)
Mean: \( \frac{231827025805447815633938549528711882730773}{1584095419914000000000000000} \approx 146346629686003.0 \)
Sample standard deviation: \( \frac{\sqrt{537437630761237503670180113135399760640627968340862811828261052185294608236011775290}}{1584095419914000000000000000} \approx 462788648343409.0 \)
Median: \( \frac{8003451}{2} = 4001725.5 \)
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