If 𝑢 = 𝑙𝑜𝑔 [𝑥8+𝑦8+𝑧8

𝑥+2𝑦+3𝑧 ], prove that 𝑥

𝜕𝑢

𝜕𝑥 + 𝑦

𝜕𝑢

𝜕𝑦 + 𝑧

𝜕𝑢

𝜕𝑧

= 7

asked by guest
on Nov 16, 2024 at 5:02 am



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