6√27+6√27-6√27

asked by guest
on Jan 16, 2025 at 2:04 am



You asked:

Evaluate the expression: \(6 \sqrt{27} + 6 \sqrt{27} - 6 \sqrt{27}\)

MathBot Answer:

\[6 \sqrt{27} + 6 \sqrt{27} - 6 \sqrt{27} = 18 \sqrt{3} \approx 31.1769145362397912834940341471057\]

\[\begin{aligned}6 \sqrt{27} + 6 \sqrt{27} - 6 \sqrt{27}& = 6 \cdot \sqrt{27} + 6 \cdot \sqrt{27} - 6 \cdot \sqrt{27}\\& = 6 \cdot 3 \cdot \sqrt{3} + 6 \cdot \sqrt{27} - 6 \cdot \sqrt{27}\\& = 18 \cdot \sqrt{3} + 6 \cdot \sqrt{27} - 6 \cdot \sqrt{27}\\& = 18 \cdot \sqrt{3} + 6 \cdot 3 \cdot \sqrt{3} - 6 \cdot \sqrt{27}\\& = 18 \cdot \sqrt{3} + 18 \cdot \sqrt{3} - 6 \cdot \sqrt{27}\\& = 18 \cdot \sqrt{3} + 18 \cdot \sqrt{3} - 6 \cdot 3 \cdot \sqrt{3}\\& = 18 \cdot \sqrt{3} + 18 \cdot \sqrt{3} - 18 \cdot \sqrt{3}\\& = 36 \cdot \sqrt{3} - 18 \cdot \sqrt{3}\\& = 18 \cdot \sqrt{3}\end{aligned}\]

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