sequence periodic: 1, 1, 2, 3, 2, 1, 1, 2, 3, 2, 1, 1, 2, 3, 2, 1, 1, 2, 3, 2, 1, 1, 2, 3, 2, 1, 1, 2, 3, 2, 1, 1, 2, 3, 2, ...
linear recurrence: a(n) = a(n-5) for n >= 6
What's the continued fraction expansion?
MathBot Answer:
MathBot is working on a solution to your problem.
