Be f: [0, 1] ➝ R the function f(u) = u³·². Be R the triangular region with (0;0), (1;0), (0;1). So ∫ ∫R f (x + y) dA is equal to:
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
Be f: [0, 1] ➝ R the function f(u) = u³·². Be R the triangular region with (0;0), (1;0), (0;1). So ∫ ∫R f (x + y) dA is equal to:
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.