volume of cone with diameter 15250mm and height 500mm

asked by guest
on Mar 29, 2025 at 7:15 am



MathBot Answer:

The volume of a cone is 29070312500π330442360062.52mm3\frac{29070312500 \pi}{3} \approx 30442360062.52\, \text{mm}^3.

Note: Approximate solutions are rounded to the nearest hundredths place.


Given: d=15250h=500\begin{aligned}d&=15250\\h&=500\end{aligned}

Volume

The volume of a cone is given by the equation: V=13πr2h\begin{aligned}V&=\frac{1}{3} \pi r^{2} h\end{aligned} where VV is volume, rr is radius, and hh is height.

Need:d=2r15250=2rr=7625\begin{aligned}d&=2 r\end{aligned} \quad \Rightarrow \quad \begin{aligned}15250&=2 r\end{aligned} \quad \Rightarrow \quad \begin{aligned}r&=7625\end{aligned}

Solution:V=13πr2hV=13π(7625)2(500)V=29070312500π3\begin{aligned}V&=\frac{1}{3} \pi r^{2} h\\V&=\frac{1}{3} \pi \left(7625\right)^{2} \left(500\right)\\V&=\frac{29070312500 \pi}{3}\end{aligned}


A right cone is a three dimensional solid with one vertex, one flat face, and one curved surface pointed towards the top, called apex. The circular face is called the base. The radius r is the distance between the center of the base and any point on the circumference of the base. The diameter d is twice the radius, forming a line segment passing through the center of the base. The height h is the distance between the center of the base and the apex, forming a line segment perpendicular to the base. The slant height H is the distance between the apex and any point on the circumference of the base.


The slant height H of a cone is the hypotenuse of the right triangle with legs being the radius and height. H=r2+h2H = \sqrt{r^{2} + h^{2}}

The (base) circumference C, or base perimeter PB, of a cone is the distance around the base.C=PB=2πr=πd\begin{aligned} C = P_{B} &= 2 \pi r \\ &= \pi d \end{aligned}

The base area AB of a cone is the region enclosed inside the base. AB=πr2A_{B} = \pi r^{2}

The lateral surface area AL of a cone is the area of the curved surface. AL=πrH=πrr2+h2\begin{aligned} A_{L} &= \pi r H \\ &= \pi r \sqrt{r^{2} + h^{2}} \end{aligned}

The surface area S of a cone is the region occupied by its base and curved surface. S=AB+AL=πr(r+H)=πr(r+r2+h2)\begin{aligned} S &= A_{B} + A_{L} \\ &= \pi r (r + H) \\ &= \pi r (r + \sqrt{r^{2} + h^{2}}) \end{aligned}

The volume V of a cone is the amount of space it occupies. V=13ABh=13πr2h\begin{aligned} V &= \frac{1}{3} A_{B} h \\ &= \frac{1}{3} \pi r^{2} h \end{aligned}