Si n^n=4,calcula n^(n^(〖n+1〗^(〖n+2〗^(〖n+3〗^(n+8) ) ) ) )
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Si n^n=4,calcula n^(n^(〖n+1〗^(〖n+2〗^(〖n+3〗^(n+8) ) ) ) )
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.