Integrate[Sqrt[4-9Power[x,2]],{x,0,Divide[2,3]}]

asked by guest
on Sep 21, 2024 at 10:57 am



You asked:

Evaluate the integral: \(\int_{0}^{\frac{2}{3}}{\sqrt{4 - 9 \cdot {x}^{2}}}dx\)

MathBot Answer:

Definite integral

\[\int_{0}^{\frac{2}{3}}{\sqrt{4 - 9 \cdot {x}^{2}}}dx = \frac{\pi}{3} \approx 1.04719755119659774615421446109317\]

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