(8x^6y^-15z^3)^(2/3) *(49x^-2y^8x^2)^(-1/2)
asked by guest
on Nov 17, 2024 at 12:26 pm
You asked:
Evaluate the expression:
(8x6y−15z3)32(49x−2y8x2)2−1
MathBot Answer:
(8x6y−15z3)32(49x−2y8x2)2−1=7y84(y15x6z3)32
If the variables x, y, z are real, then:
7y84(y15x6z3)32=7∣y4∣4(y15x6z3)32