(8x^6y^-15z^3)^(2/3) *(49x^-2y^8x^2)^(-1/2)

asked by guest
on Nov 17, 2024 at 12:26 pm



You asked:

Evaluate the expression: (8x6y15z3)23(49x2y8x2)12{\left( 8 {x}^{6} {y}^{-15} {z}^{3} \right)}^{\frac{2}{3}} {\left( 49 {x}^{-2} {y}^{8} {x}^{2} \right)}^{\frac{-1}{2}}

MathBot Answer:

(8x6y15z3)23(49x2y8x2)12=4(x6z3y15)237y8{\left( 8 {x}^{6} {y}^{-15} {z}^{3} \right)}^{\frac{2}{3}} {\left( 49 {x}^{-2} {y}^{8} {x}^{2} \right)}^{\frac{-1}{2}} = \frac{4 \left(\frac{x^{6} z^{3}}{y^{15}}\right)^{\frac{2}{3}}}{7 \sqrt{y^{8}}}

If the variables xx, yy, zz are real, then: 4(x6z3y15)237y8=4(x6z3y15)237y4\frac{4 \left(\frac{x^{6} z^{3}}{y^{15}}\right)^{\frac{2}{3}}}{7 \sqrt{y^{8}}} = \frac{4 \left(\frac{x^{6} z^{3}}{y^{15}}\right)^{\frac{2}{3}}}{7 \left|{y^{4}}\right|}