Solve for the domain: y = √[(x+3)/(x-1)]
You asked:
Find domain of \(y = \sqrt{\frac{x + 3}{x - 1}}\)
MathBot Answer:
Set notation:
\(\displaystyle\left\{x \in \mathbb{R}:\frac{x + 3}{x - 1} \geq 0\wedge x \neq 1\right\}\)
Interval notation:
\(\displaystyle\left(-\infty, -3\right] \cup \left(1, \infty\right)\)