50-30e^-0.2t=49.99

asked by guest
on Nov 15, 2024 at 5:56 am



You asked:

Investigate the equation: \(50 - 30 \cdot {e}^{-0.2} \cdot t = 49.99\).

MathBot Answer:

The solution is: \[t = \frac{e^{\frac{1}{5}}}{3000} \approx 0.00040713425\]


\[\begin{aligned}t \left(- \frac{30}{e^{0.2}}\right) + 50 &= 49.99\\t \left(- \frac{30}{e^{0.2}}\right) &= 0.01\\t &= \frac{e^{0.2}}{3000}\end{aligned}\]


\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).