(2x-13)*(x-5)^2
asked by guest on Jan 28, 2025 at 3:43 pm
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MathBot Answer:
(2x−13)(x−5)2=(2x−13)(x−5)2\displaystyle \left(2 x - 13\right) {\left( x - 5 \right)}^{2} = \left(2 x - 13\right) \left(x - 5\right)^{2} (2x−13)(x−5)2=(2x−13)(x−5)2
(2x−13)(x−5)2=2x3−33x2+180x−325\left(2 x - 13\right) {\left( x - 5 \right)}^{2} = 2 x^{3} - 33 x^{2} + 180 x - 325(2x−13)(x−5)2=2x3−33x2+180x−325