factorize
m2m^{2}m2/5 + m/5 + 2am/5
asked by guest on Nov 14, 2024 at 2:49 am
You asked:
MathBot Answer:
The polynomial factors into the product: m25+m5+2am5=m(2a+m+1)5\frac{{m}^{2}}{5} + \frac{m}{5} + \frac{2 a m}{5} = \frac{m \left(2 a + m + 1\right)}{5}5m2+5m+52am=5m(2a+m+1)