(5.6+2.3)-1.1(2.5) =

asked by guest
on Jan 22, 2025 at 9:50 pm



You asked:

Evaluate the expression: \(5.6 + 2.3 - 1.1 \cdot 2.5\)

MathBot Answer:

\[5.6 + 2.3 - 1.1 \cdot 2.5 = \frac{103}{20} = 5.15\]

\[\begin{aligned}5.6 + 2.3 - 1.1 \cdot 2.5& = 5 + \frac{6}{10} + 2 + \frac{3}{10} - \left(1 + \frac{1}{10}\right) \cdot \left(2 + \frac{5}{10}\right)\\& = 5 + \frac{3}{5} + 2 + \frac{3}{10} - \left(1 + \frac{1}{10}\right) \cdot \left(2 + \frac{5}{10}\right)\\& = 5 + \frac{3}{5} + 2 + \frac{3}{10} - \frac{11}{10} \cdot \left(2 + \frac{5}{10}\right)\\& = 5 + \frac{3}{5} + 2 + \frac{3}{10} - \frac{11}{10} \cdot \left(2 + \frac{1}{2}\right)\\& = 5 + \frac{3}{5} + 2 + \frac{3}{10} - \frac{11}{10} \cdot \frac{5}{2}\\& = 5 + \frac{3}{5} + 2 + \frac{3}{10} - \frac{11}{4}\\& = \frac{28}{5} + 2 + \frac{3}{10} - \frac{11}{4}\\& = \frac{38}{5} + \frac{3}{10} - \frac{11}{4}\\& = \frac{79}{10} - \frac{11}{4}\\& = \frac{103}{20}\end{aligned}\]

+ Submit Question