\frac{2}{3!}+\frac{4}{5!}+\frac{6}{7!}+\frac{8}{9!}+...=\frac{1}{e}
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
\frac{2}{3!}+\frac{4}{5!}+\frac{6}{7!}+\frac{8}{9!}+...=\frac{1}{e}
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.