$x^{4}$ -8 $x^{2}$ +8=0
You asked:
Solve the equation \({x}^{4} - 8 \cdot {x}^{2} + 8 = 0\) for the variable \(x\).
MathBot Answer:
The 4 solutions to the equation are: \[\begin{aligned}x &= \sqrt{4 - 2 \sqrt{2}} \approx 1.0823922\\x &= \sqrt{4 + 2 \sqrt{2}} \approx 2.6131259\\x &= - \sqrt{4 - 2 \sqrt{2}} \approx -1.0823922\\x &= - \sqrt{4 + 2 \sqrt{2}} \approx -2.6131259\end{aligned}\]