d^2+14d+48
asked by guest on Mar 20, 2025 at 6:06 pm
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MathBot Answer:
d2+14d+48=d2+14d+48\displaystyle {d}^{2} + 14 d + 48 = d^{2} + 14 d + 48 d2+14d+48=d2+14d+48
d2+14d+48=(d+6)(d+8){d}^{2} + 14 d + 48 = \left(d + 6\right) \left(d + 8\right)d2+14d+48=(d+6)(d+8)