factorize
14$x^{2}$y-21x$y^{2}$+28xy
You asked:
Factor the expression: \(\displaystyle 14 \cdot {x}^{2} \cdot y - 21 x \cdot {y}^{2} + 28 x y\)
MathBot Answer:
The polynomial factors into the product: \[14 \cdot {x}^{2} \cdot y - 21 x \cdot {y}^{2} + 28 x y = 7 x y \left(2 x - 3 y + 4\right)\]