5x5^{x}5x - 5x−15^{x-1}5x−1 / 4* 5x−15^{x-1}5x−1
asked by guest on Mar 22, 2025 at 7:34 pm
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MathBot Answer:
5x−5x−14⋅5x−1=5x−52x−24\displaystyle {5}^{x} - \frac{{5}^{x - 1}}{4} \cdot {5}^{x - 1} = 5^{x} - \frac{5^{2 x - 2}}{4} 5x−45x−1⋅5x−1=5x−452x−2
5x−5x−14⋅5x−1=−52x100+5x{5}^{x} - \frac{{5}^{x - 1}}{4} \cdot {5}^{x - 1} = - \frac{5^{2 x}}{100} + 5^{x}5x−45x−1⋅5x−1=−10052x+5x
5x−5x−14⋅5x−1=−5x(5x−100)100{5}^{x} - \frac{{5}^{x - 1}}{4} \cdot {5}^{x - 1} = - \frac{5^{x} \left(5^{x} - 100\right)}{100}5x−45x−1⋅5x−1=−1005x(5x−100)
