($8/125)^{2x-1}$ = $(25/4)^{2x}$

asked by guest
on Nov 15, 2024 at 6:48 am



You asked:

Solve the equation \({\left( \frac{8}{125} \right)}^{2 x - 1} = {\left( \frac{25}{4} \right)}^{2 x}\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = \frac{3}{10} = 0.3\]

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