(2+m)(5-m)
asked by guest on Mar 17, 2025 at 6:31 am
You asked:
MathBot Answer:
(2+m)(5−m)=(5−m)(m+2)\left(2 + m\right) \left(5 - m\right) = \left(5 - m\right) \left(m + 2\right)(2+m)(5−m)=(5−m)(m+2)
(2+m)(5−m)=−m2+3m+10\left(2 + m\right) \left(5 - m\right) = - m^{2} + 3 m + 10(2+m)(5−m)=−m2+3m+10
(2+m)(5−m)=−(m−5)(m+2)\left(2 + m\right) \left(5 - m\right) = - \left(m - 5\right) \left(m + 2\right)(2+m)(5−m)=−(m−5)(m+2)