integrate cos(2x)/sin (2x)-3

asked by guest
on Oct 22, 2024 at 12:10 pm



You asked:

Evaluate the integral: \(\int{\frac{\cos\left( 2 x \right)}{\sin\left( 2 x \right)} - 3}dx\)

MathBot Answer:

Antiderivative

\[\int{\frac{\cos\left( 2 x \right)}{\sin\left( 2 x \right)} - 3}dx = \frac{\log{\left(\sin{\left(2 x \right)} \right)}}{2} - 3 x + C\]

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