y'+xe^(-x/2)=0
You asked:
Investigate the equation: \(y^{\prime} + x \cdot {e}^{\frac{-x}{2}} = 0\).
MathBot Answer:
\[y{\left(x \right)} = 4 e^{- \frac{x}{2}} + 2 x e^{- \frac{x}{2}} + C_{1}\]
\(C_{1}\) is an arbitrary constant.
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).