In the given figure, AD is bisector of ∠BAC and ∠CPD = ∠BPD. Prove that ΔCAP ≌ ΔBAP.
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In the given figure, AD is bisector of ∠BAC and ∠CPD = ∠BPD. Prove that ΔCAP ≌ ΔBAP.
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.