6.79mA/(120)(5000)(0.1mF)

asked by guest
on Sep 20, 2024 at 6:10 am



You asked:

Evaluate the expression: \(\frac{6.79 m A}{120 \cdot 5000 \cdot 0.1 m F}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{6.79 m A}{120 \cdot 5000 \cdot 0.1 m F} = \frac{679 A}{6000000 F} \)

Expanded

\[\frac{6.79 m A}{120 \cdot 5000 \cdot 0.1 m F} = \frac{679 A}{6000000 F}\]

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