A^2+3B^t-C^2\:\:,\:\:A=\begin{pmatrix}-1&3\\ \:\:2&-6\end{pmatrix},\:\:C=\begin{pmatrix}9&7\\ \:\:2&6\end{pmatrix},\:b=\begin{pmatrix}1&-5\\ \:\:-3&-1\end{pmatrix}

asked by guest
on Oct 06, 2024 at 3:44 pm



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.


+ Submit Question