(TAxL)/(L+A)
asked by guest on Mar 17, 2025 at 4:33 am
You asked:
MathBot Answer:
TAxLL+A=ALTxA+L\displaystyle \frac{T A x L}{L + A} = \frac{A L T x}{A + L} L+ATAxL=A+LALTx
TAxLL+A=ALTxA+L\frac{T A x L}{L + A} = \frac{A L T x}{A + L}L+ATAxL=A+LALTx