aa-b(a-b)-b(a-b)-bb
asked by guest on Mar 26, 2025 at 5:28 pm
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MathBot Answer:
a⋅a−b(a−b)−b(a−b)−b⋅b=a2−b2−2b(a−b)\displaystyle a \cdot a - b \left(a - b\right) - b \left(a - b\right) - b \cdot b = a^{2} - b^{2} - 2 b \left(a - b\right) a⋅a−b(a−b)−b(a−b)−b⋅b=a2−b2−2b(a−b)
a⋅a−b(a−b)−b(a−b)−b⋅b=a2−2ab+b2a \cdot a - b \left(a - b\right) - b \left(a - b\right) - b \cdot b = a^{2} - 2 a b + b^{2}a⋅a−b(a−b)−b(a−b)−b⋅b=a2−2ab+b2
a⋅a−b(a−b)−b(a−b)−b⋅b=(a−b)2a \cdot a - b \left(a - b\right) - b \left(a - b\right) - b \cdot b = \left(a - b\right)^{2}a⋅a−b(a−b)−b(a−b)−b⋅b=(a−b)2