120=4*10^-4(R+10*10^3)

asked by guest
on Jan 12, 2025 at 9:11 pm



You asked:

Solve the equation \(120 = 4 \cdot {10}^{-4} \left(R + 10 \cdot {10}^{3}\right)\) for the variable \(R\).

MathBot Answer:

The solution is: \[R = 290000\]

\[\begin{aligned}120 &= \frac{R}{2500} + 4\\- \frac{R}{2500} &= -116\\R &= 290000\end{aligned}\]

+ Submit Question