(20+1)/(10^((2-6/2) )+1)
You asked:
Evaluate the expression: \(\frac{20 + 1}{{10}^{2 - \frac{6}{2}} + 1}\)
MathBot Answer:
\[\frac{20 + 1}{{10}^{2 - \frac{6}{2}} + 1} = \frac{210}{11} = 19.\overline{09}\]
\[\begin{aligned}\frac{20 + 1}{{10}^{2 - \frac{6}{2}} + 1}& = \left(20 + 1\right) \cdot \frac{1}{10^{2 - 3} + 1}\\& = 21 \cdot \frac{1}{10^{2 - 3} + 1}\\& = 21 \cdot \frac{1}{\frac{1}{10} + 1}\\& = 21 \cdot \frac{1}{\frac{11}{10}}\\& = \frac{210}{11}\end{aligned}\]